URL Fragment Ignored When Parsing Query String – # Explained

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Explain that URL fragments are separate from the query component and are intentionally ignored by query parsing.

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2 parameters2 unique keys

URL query and fragment behavior

Why the # fragment is ignored when parsing query parameters

A URL fragment begins at # and is a separate URL component from the query. Query parsing therefore reads parameters before the fragment and does not expose the fragment as a key or value. This tool is free to use. No account or payment is required.

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What you can do here

  • Browser-native URLSearchParams behavior
  • Full URL and raw query parsing
  • Repeated parameter preservation
  • JSON object to query construction
  • Browser-local processing

Steps

  1. Paste the full URL into Parse to JSON.
  2. Locate the # separator after the query string.
  3. Move data that must reach query parsing before # or encode it as part of a parameter value.

Fragments and queries have different jobs

The query begins after ? and ends before #. The fragment identifies a client-side location or state and is not part of the query parameter collection.

If a literal # belongs inside a parameter value, it must be percent-encoded so it is not interpreted as the fragment delimiter.

Full URL with a fragment

Only q and lang appear in the parsed output.

Full URL

https://example.com/search?q=vetatool&lang=en#results

Parsed JSON

{
  "q": "vetatool",
  "lang": "en"
}

Common questions

Frequently asked questions

Is #results a query parameter?

No. It is the URL fragment.

Does a browser send the fragment to a server in an HTTP request?

The fragment is normally handled client-side and is not part of the HTTP request target sent to the server.

How do I include a literal # in a parameter?

Percent-encode it as %23 inside the parameter value.

Debugging a specific Query String issue? Browse Query String troubleshooting.